Roll Up MY Rim and Win!!

Well, it’s that time of year, once again.  For anyone who has read my blogs over time, you may remember my posts on the probability of winning on a Roll Up the Rim Tim Horton’s cup.  If not, check them out here and here.  Last year I thought to look at the odds and how well they matched up with my hot beverage purchases.  I used the breakdown below to score my results (last year’s end totals are displayed):

Drinks for me: 23
Drinks for others: 6
Drinks for me, purchased by others: 4

Total Drinks Purchased: 33

Winning cups for me: 2
Winning cups for others: 2
Winning cups for me, purchased by others: 0

Total winning cups: 4

Odds for me: 2 in 23
Odds for others: 2 in 6
Odds for me, purchased by others: 0 in 4

Total odds: 4 in 33

This year, Tim Horton’s (I refuse to use the public relations and media friendly moniker “Tim Hortons” as it pays little respect to the founder of Tim Horton’s and separates the chain’s history from the man that started it all, hence, Tim Horton’s–or the coffee shop belonging to Tim Horton) claims that the odds are 1 in 6.  Let’s see about that one…

Drinks for me (so far): 13
Drinks for others (so far): 7
Drinks for me, purchased by others: 1 (Nya:weh, Mr. Sowden)

Total Drinks Purchased: 21

Winning cups for me: 2
Winning cups for others: 3
Winning cups for me, purchased by others: 0

Total Winning Cups: 5

Odds for me: 2 in 13
Odds for others:  3 in 7
Odds for me, purchased by others:  0 for 1

Total odds:  5 in 21.

Consider tracking your own purchases but more importantly, discuss and utilize real life instances of probability to enable students to make real life connections to the math they are learning.

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About Mr. R.G.

I'm a father, a teacher and a reader for life.

Posted on March 8, 2012, in probability, Roll Up the Rim, tim hortons. Bookmark the permalink. Leave a comment.

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